armi.materials.hastelloyN module
Hastelloy-N is a high-nickel structural material invented by ORNL for handling molten fluoride salts.
- class armi.materials.hastelloyN.HastelloyN[source]
Bases:
Material
Hastelloy N alloy (UNS N10003).
[Haynes] (1,2,3)Haynes International, H-2052D 2020 (http://haynesintl.com/docs/default-source/pdfs/new-alloy-brochures/corrosion-resistant-alloys/brochures/n-brochure.pdf)
[SAB]Sabharwall, et. al. Feasibility Study of Secondary Heat Exchanger Concepts for the Advanced High Temperature Reactor INL/EXT-11-23076, 2011
- materialIntro = 'Hastelloy N alloy is a nickel-base alloy that was invented at Oak RIdge National Laboratories as a container material for molten fluoride salts. It has good oxidation resistance to hot fluoride salts in the temperature range of 704 to 871C (1300 to 1600F)'
- propertyValidTemperature = {'heat capacity': ((373.15, 973.15), 'K'), 'thermal conductivity': ((473.15, 973.15), 'K'), 'thermal expansion': ((293.15, 1173.15), 'K')}
Dictionary of valid temperatures over which the property models are valid in the format ‘Property Name’: ((Temperature_Lower_Limit, Temperature_Upper_Limit), Temperature_Units)
- refTempK = 293.15
- thermalConductivity(Tk=None, Tc=None)[source]
Calculates the thermal conductivity of Hastelloy N. Second order polynomial fit to data from [Haynes].
- heatCapacity(Tk=None, Tc=None)[source]
Calculates the specific heat capacity of Hastelloy N. Sixth order polynomial fit to data from Table 2-20 [SAB] (R^2=0.97).
- linearExpansionPercent(Tk=None, Tc=None)[source]
average thermal expansion dL/L. Used for computing hot dimensions.
- meanCoefficientThermalExpansion(Tk=None, Tc=None)[source]
Mean coefficient of thermal expansion for Hastelloy N. Second order polynomial fit of data from [Haynes].
- density(Tk: float = None, Tc: float = None) float
Return density that preserves mass when thermally expanded in 3D (in g/cm^3).
Notes
Since refDens is specified at the material-dep reference case, we don’t need to specify the reference temperature. It is already consistent with linearExpansion Percent. - p*(dp/p(T) + 1) =p*( p + dp(T) )/p = p + dp(T) = p(T) - dp/p = (1-(1 + dL/L)**3)/(1 + dL/L)**3